The square root of a number is that number the product of which itself gives the given number, ie, the square root of 400 is 20, the square root of 625 is 25.
The expression √16 is read as root sixteen. Some times also square root of 16, or radical of sixteen.
i) By prime factorization method:
When a given number is a perfect square we resolve it into prime factors and take the product of prime factors choosing one out of every two.
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4356 = 2×2×3×3×11×11
Hence √4356 = 2×3×11 = 66
Thus from the above example it is clear that in order to find the complete square root of a given number every prime factor of that number should be repeated twice. Thus, we can make a number which is not a perfect square, a perfect square by multiplying or dividing the number by those factors of it which are not contained in pairs.
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Ans: Resolving 484 as the product of primes, we get,
√484 = √(2 × 2 × 11 × 11) = 2 × 11
Therefore, √484 = 22.
The square root of 1764 by prime factorization, we get
1764 = 2 x 2 x 3 x 3 x 7 x 7.
√1764 = √(2 x 2 x 3 x 3 x 7 x 7)
= 2 x 3 x 7
Therefore, √1764 = 42.
The cube root of a number is that number the cube of which itself gives the given number i.e. the cube root of 125 is 5. The cube root of a number is denoted by the symbol . The expression is read as cube root of 64.which is 4.
To find the cube root of an integer:
By prime factorization method:
When a given number is a perfect cube, we resolve it into prime factors and take the product of prime factors, choosing one out of every three.
Ans:
Hence 74088 = 2×2×2×7×7×7×3×3×3 =2³×3³×7³
and the cube root of 74088 = 2×3×7 = 42
Ans: In 19683, 19 lies between 2³ and 3³, so left digit is 2 and 683 ends with 3, so right digit is 7. Thus 27 is a cube root of 19683.
Ans: By prime factorization, we have
343 = 7 × 7 × 7
= (7 × 7 × 7).
Therefore, ∛343 = 7.